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makefile: define GIT_VERSION, statically include *VERSION in release tarballs

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Michael Stapelberg 2010-09-22 20:14:42 +02:00
parent e137e33faa
commit 7bc1e2cd4c
1 changed files with 4 additions and 1 deletions
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5
Makefile
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@ -3,10 +3,12 @@ CFLAGS+=-g
CFLAGS+=-std=gnu99
CFLAGS+=-pedantic
CFLAGS+=-DPREFIX=\"\"
CFLAGS+=-DVERSION=\"${GIT_VERSION}\"
CFLAGS+=-Iinclude
LDFLAGS+=-lconfuse
VERSION=$(shell git describe --tags --abbrev=0)
VERSION:=$(shell git describe --tags --abbrev=0)
GIT_VERSION:="$(shell git describe --tags --always) ($(shell git log --pretty=format:%cd --date=short -n1))"
ifeq ($(shell uname),Linux)
CFLAGS+=-DLINUX
@ -64,5 +66,6 @@ release:
mkdir i3status-${VERSION}/man
find src -maxdepth 1 -type f \( -regex ".*\.\(c\|h\)" \) -exec cp '{}' i3status-${VERSION}/src \;
find man -maxdepth 1 -type f \( -regex ".*\.\(1\|man\|conf\)" -or -name "Makefile" \) -exec cp '{}' i3status-${VERSION}/man \;
sed -e 's/^GIT_VERSION:=\(.*\)/GIT_VERSION=${GIT_VERSION}/g;s/^VERSION:=\(.*\)/VERSION=${VERSION}/g' Makefile > i3status-${VERSION}/Makefile
tar cjf i3status-${VERSION}.tar.bz2 i3status-${VERSION}
rm -rf i3status-${VERSION}